2[t-(4+18)+8]=2(t+10)

Solution for 2[t-(4+18)+8]=2(t+10) equation:

Simplifying
2[t + -1(4 + 18) + 8] = 2(t + 10)

Combine like terms: 4 + 18 = 22
2[t + -1(22) + 8] = 2(t + 10)

Multiply -1 * 22
2[t + -22 + 8] = 2(t + 10)

Reorder the terms:
2[-22 + 8 + t] = 2(t + 10)

Combine like terms: -22 + 8 = -14
2[-14 + t] = 2(t + 10)
[-14 * 2 + t * 2] = 2(t + 10)
[-28 + 2t] = 2(t + 10)

Reorder the terms:
-28 + 2t = 2(10 + t)
-28 + 2t = (10 * 2 + t * 2)
-28 + 2t = (20 + 2t)

Add '-2t' to each side of the equation.
-28 + 2t + -2t = 20 + 2t + -2t

Combine like terms: 2t + -2t = 0
-28 + 0 = 20 + 2t + -2t
-28 = 20 + 2t + -2t

Combine like terms: 2t + -2t = 0
-28 = 20 + 0
-28 = 20

Solving
-28 = 20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.